OK, here are the solutions I received to the home work quiz. Thanks to Alan D. McIntire, Peter Gallagher, Jan Pompe, BobD and Josh for contributions.

**1:**

(1+1+1)!=6

1*1*1 = 6^0

1 x 1 x 1 = âˆžâˆš6

11|4 + 1 = 6 where the 4 is a subscript indicating â€œbase 4â€³

1Ã—1+1 = Ï†(6)

**2:**

(2*2) – 2 = 6

2 + 2 + 2 = 6

**3:**

(3*3) – 3 = 6

Ï†(3+3+3) =6

**4:**

4^(1/2) + 4^(1/2) + 4^(1/2) = 6

4 + 4 – 4^(1/2) = 6

**5:**

(5/5) + 5 = 6

5 + 5 / 5 = 6

**6:**

6+6-6=6

6 – 6 + 6 = 6

Ï†(6+6+6) =6

**7:**

7 – (7/7) = 6

**8:**

8-8^0-8^0 = 6

8^(1/3) + 8^(1/3) + 8^(1/3) = 6

8 – (8+8)^.25 = 6

Γ(8 -8/8) = 6!

**9:**

(9 + 9) / 9^ (1/2) = 6

9^(1/2) x 9^(1/2) â€“ 9^(1/2) = 6

9 – (9 / 9^.5) = 6

Ï† is Euler’s Totient Function.

Γ is the Gamma function.

And my solution where n is any number:

(n^0 + n^0 + n^0)! = 6

just to test I’ve got this totient thingy

hows

1×1+1 = φ(6)

just to test I’ve got this totient thingy

hows

1×1+1 = φ(6)

A couple of others:

1:

11|4 + 1 = 6 where the 4 is a subscript indicating “base 4”

4:

4 + 4 – 4^(1/2) = 6

By the way:

4! / 4 = 6

is true but lacks a 4.

A couple of others:

1:

11|4 + 1 = 6 where the 4 is a subscript indicating “base 4”

4:

4 + 4 – 4^(1/2) = 6

By the way:

4! / 4 = 6

is true but lacks a 4.

I think solutions like

8 – (8+8)^.25 = 6

and

(9 + 9) / 9^ (1/2) = 6

are cheating because of those additional numbers, 0.25 and 1/2.

Why are ^0.25 and ^ 1/2

allowed, and not -21, resulting in trivial solutions

like 9+9+9 -21 =6 .

You could have gotten around it by throwing in SQRT(SQRT) and SQRT.

My own solution to 8 was

Gamma (8 -8/8) = 6!

I couldn’t solve the 9 series without the

SQRT.

I think solutions like

8 – (8+8)^.25 = 6

and

(9 + 9) / 9^ (1/2) = 6

are cheating because of those additional numbers, 0.25 and 1/2.

Why are ^0.25 and ^ 1/2

allowed, and not -21, resulting in trivial solutions

like 9+9+9 -21 =6 .

You could have gotten around it by throwing in SQRT(SQRT) and SQRT.

My own solution to 8 was

Gamma (8 -8/8) = 6!

I couldn’t solve the 9 series without the

SQRT.

Its all good. Hope people learned something. Cheers

Its all good. Hope people learned something. Cheers

Alan #3

there is a difference between defining operations on terms and adding extra ones.

Alan #3

there is a difference between defining operations on terms and adding extra ones.

Pingback: zobacz tutaj

Pingback: zobacz

Pingback: link do strony

Pingback: opieka poszpitalna wroclaw

Pingback: kiedy dysponowac super cialo

Pingback: jak zalozyc sklep internetowy

Pingback: Bench Craft Company News

Pingback: colonie de vacances

Pingback: zdrowesoki.blogspot.com

Pingback: zakupzlota.blog4u.pl

Pingback: travel