# The home work quiz

OK, here are the solutions I received to the home work quiz. Thanks to Alan D. McIntire, Peter Gallagher, Jan Pompe, BobD and Josh for contributions.

1:
(1+1+1)!=6
1*1*1 = 6^0
1 x 1 x 1 = âˆžâˆš6
11|4 + 1 = 6 where the 4 is a subscript indicating â€œbase 4â€³
1Ã—1+1 = Ï†(6)
2:
(2*2) – 2 = 6
2 + 2 + 2 = 6
3:
(3*3) – 3 = 6
Ï†(3+3+3) =6
4:
4^(1/2) + 4^(1/2) + 4^(1/2) = 6
4 + 4 – 4^(1/2) = 6
5:
(5/5) + 5 = 6
5 + 5 / 5 = 6
6:
6+6-6=6
6 – 6 + 6 = 6
Ï†(6+6+6) =6
7:
7 – (7/7) = 6
8:
8-8^0-8^0 = 6
8^(1/3) + 8^(1/3) + 8^(1/3) = 6
8 – (8+8)^.25 = 6
Γ(8 -8/8) = 6!
9:
(9 + 9) / 9^ (1/2) = 6
9^(1/2) x 9^(1/2) â€“ 9^(1/2) = 6
9 – (9 / 9^.5) = 6

Ï† is Euler’s Totient Function.
Γ is the Gamma function.

And my solution where n is any number:
(n^0 + n^0 + n^0)! = 6

## 0 thoughts on “The home work quiz”

1. Jan Pompe says:

just to test I’ve got this totient thingy

hows
1×1+1 = φ(6)

2. Jan Pompe says:

just to test I’ve got this totient thingy

hows
1×1+1 = φ(6)

3. BobD says:

A couple of others:
1:
11|4 + 1 = 6 where the 4 is a subscript indicating “base 4”

4:
4 + 4 – 4^(1/2) = 6

By the way:
4! / 4 = 6
is true but lacks a 4.

4. BobD says:

A couple of others:
1:
11|4 + 1 = 6 where the 4 is a subscript indicating “base 4”

4:
4 + 4 – 4^(1/2) = 6

By the way:
4! / 4 = 6
is true but lacks a 4.

5. Alan D. McIntire says:

I think solutions like

8 – (8+8)^.25 = 6

and

(9 + 9) / 9^ (1/2) = 6

are cheating because of those additional numbers, 0.25 and 1/2.

Why are ^0.25 and ^ 1/2
allowed, and not -21, resulting in trivial solutions
like 9+9+9 -21 =6 .

You could have gotten around it by throwing in SQRT(SQRT) and SQRT.

My own solution to 8 was
Gamma (8 -8/8) = 6!

I couldn’t solve the 9 series without the
SQRT.

6. Alan D. McIntire says:

I think solutions like

8 – (8+8)^.25 = 6

and

(9 + 9) / 9^ (1/2) = 6

are cheating because of those additional numbers, 0.25 and 1/2.

Why are ^0.25 and ^ 1/2
allowed, and not -21, resulting in trivial solutions
like 9+9+9 -21 =6 .

You could have gotten around it by throwing in SQRT(SQRT) and SQRT.

My own solution to 8 was
Gamma (8 -8/8) = 6!

I couldn’t solve the 9 series without the
SQRT.

7. Its all good. Hope people learned something. Cheers

8. Its all good. Hope people learned something. Cheers

9. Jan Pompe says:

Alan #3

there is a difference between defining operations on terms and adding extra ones.

10. Jan Pompe says:

Alan #3

there is a difference between defining operations on terms and adding extra ones.

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