A maths home work quiz

I give you 3 digits and a result and you must put all the signs necessary to restore the equality.

I’ll give you an example. The remainder you solve by yourself.

2 + 2 + 2 = 6

Easy isn’t this? It’s the same for the remainder.

1 1 1 = 6
2 2 2 = 6
3 3 3 = 6
4 4 4 = 6
5 5 5 = 6
6 6 6 = 6
7 7 7 = 6
8 8 8 = 6
9 9 9 = 6

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0 thoughts on “A maths home work quiz

  1. I think the solutions to 3,4,5,6,7,8 and 9 are fairly straightforward. However, number 1 isn’t.
    I’ve tried to reproduce it below, the right hand side should read “the infinite root of 6”.

    1 x 1 x 1 = ∞√6

  2. I think the solutions to 3,4,5,6,7,8 and 9 are fairly straightforward. However, number 1 isn’t.
    I’ve tried to reproduce it below, the right hand side should read “the infinite root of 6”.

    1 x 1 x 1 = ∞√6

  3. Thanks David,

    for both the fun and the answer.

    I wasn’t sure whether we we could operate on both sides.

    Now I’m really curious about what Josh might be thinking. Josh?

  4. Thanks David,

    for both the fun and the answer.

    I wasn’t sure whether we we could operate on both sides.

    Now I’m really curious about what Josh might be thinking. Josh?

  5. Good mathematicians start conversations either by drawing a triple integral first, or by explaining “On one hand….”

    Digital solutions:

    On one hand I found 5 fingers + 1 thumb = 6.

    On the other hand, I found 4 fingers + 1 thumb = 5.

    (Noted asymmetry and mirroring).

    While looking for a nice solution in hand, I deduced that people smart enough to know about Euler’s Totient Function are w…….s. (wiki readers).

    Time for solution = 0.3 milliseconds.

    (This has not been peer reviewed).

  6. Good mathematicians start conversations either by drawing a triple integral first, or by explaining “On one hand….”

    Digital solutions:

    On one hand I found 5 fingers + 1 thumb = 6.

    On the other hand, I found 4 fingers + 1 thumb = 5.

    (Noted asymmetry and mirroring).

    While looking for a nice solution in hand, I deduced that people smart enough to know about Euler’s Totient Function are w…….s. (wiki readers).

    Time for solution = 0.3 milliseconds.

    (This has not been peer reviewed).

  7. More serious this time, does this fit the rules of the game? Might not work for n = 0.

    {[(n)! – (n-1)!]/3 + [(n)! – (n-1)!]/3 + [(n)! – (n-1)!]/3 } = n

    I have never really thought about the sign of the factorial of a negative integer. I guess it alternates.

    Thought time: 2 weeks

  8. More serious this time, does this fit the rules of the game? Might not work for n = 0.

    {[(n)! – (n-1)!]/3 + [(n)! – (n-1)!]/3 + [(n)! – (n-1)!]/3 } = n

    I have never really thought about the sign of the factorial of a negative integer. I guess it alternates.

    Thought time: 2 weeks

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